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CHEM 030.101.11 INTRODUCTORY CHEMISTRY MIDTERM EXAM Q & A 2026 (Complete And Verified Study material) (5pages) LEARNEXAMS What mass of NaOH is needed to prepare 800.0 mL of a solution having a pH of 12.56? (6 points) pH = 12.56. pOH = 14 – 12.56 = 1.44 Therefore, [OH- ] = 10-1.44 = 3.6 x 10-2 M Since NaOH is a strong base, conc. of NaOH = conc. of [OH- ] = 3.6 x 10-2 M moles of NaOH = molarity * volume (in L) = 3.6 x 10-2 * 0.8 L = 2.88 x 10-2 moles NaOH grams = moles * molar mass of NaOH = 1.
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